The ion of an element has 3 positive charges. | vedclass

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(D) $1$. The mass number $(A)$ of an atom is the sum of protons $(p)$ and neutrons $(n)$. Given $A = 27$ and $n = 14$,we can find the number of proton

Vedclass · Accepted Answer

$10$

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(D) $1$. The mass number $(A)$ of an atom is the sum of protons $(p)$ and neutrons $(n)$. Given $A = 27$ and $n = 14$,we can find the number of protons: $p = A - n = 27 - 14 = 13$.$2$. $A$ neutral atom has an equal number of protons and electrons. Thus,a neutral atom of this element has $13$ electrons.$3$. The ion has $3$ positive charges,which means it has lost $3$ electrons.$4$. Therefore,the number of electrons in the ion = $13 - 3 = 10$.

The ion of an element has $3$ positive charges. The mass number of the atom is $27$ and the number of neutrons is $14$. What is the number of electrons in the ion?

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