The ionic radii of K^{+},Na^{+},Al^{3+} and M | vedclass

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Question

(D) $Al^{3+}$,$Mg^{2+}$,and $Na^{+}$ are isoelectronic species,all having $10$ electrons. For isoelectronic species,the ionic radius decreases as the

Vedclass · Accepted Answer

$Al^{3+} < Mg^{2+} < Na^{+} < K^{+}$

Vedclass · Answer

(D) $Al^{3+}$,$Mg^{2+}$,and $Na^{+}$ are isoelectronic species,all having $10$ electrons. For isoelectronic species,the ionic radius decreases as the positive charge increases. Thus,the order is $Al^{3+} Comparing $Na^{+}$ and $K^{+}$,both are alkali metal ions. Since $K^{+}$ belongs to the $4^{th}$ period and $Na^{+}$ belongs to the $3^{rd}$ period,$K^{+}$ has an additional shell,so $Na^{+} Combining these,the overall order is $Al^{3+} < Mg^{2+} < Na^{+} < K^{+}$.

The ionic radii of $K^{+}$,$Na^{+}$,$Al^{3+}$ and $Mg^{2+}$ are in the order:

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