(C) The radius ratio is calculated as follows:Radius ratio $= \frac{r_{+}}{r_{-}} = \frac{0.98 \times 10^{-10} \ m}{1.81 \times 10^{-10} \ m} = 0.541$

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(C) The radius ratio is calculated as follows:Radius ratio $= \frac{r_{+}}{r_{-}} = \frac{0.98 \times 10^{-10} \ m}{1.81 \times 10^{-10} \ m} = 0.541$Since the calculated radius ratio $0.541$ lies in the range $0.414 - 0.732$,the crystal structure corresponds to an octahedral geometry.Therefore,the coordination number $(CN)$ of each ion in the $AB$ crystal lattice is $6$.

Class 12 Chemistry Solid State Crystal structure and Coordination number

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The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{-10} \ m$ and $1.81 \times 10^{-10} \ m$. The coordination number of each ion in $AB$ is.......

NEET 2016 All NEET

A
$8$
B
$2$
C
$6$
D
$4$

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Solid State

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Crystal structure and Coordination number

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The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{-10} \ m$ and $1.81 \times 10^{-10} \ m$. The coordination number of each ion in $AB$ is.......

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