The isotherms of an ideal gas at T_1, T_2, T_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For an ideal gas,the equation is $PV = nRT$,which can be rearranged as $P = (nRT) 	imes (\frac{1}{V})$.Comparing this with the equation of a stra

Vedclass · Accepted Answer

$m_1 > m_2 > m_3$

Vedclass · Answer

(D) For an ideal gas,the equation is $PV = nRT$,which can be rearranged as $P = (nRT) 	imes (\frac{1}{V})$.Comparing this with the equation of a straight line $y = mx + c$,where $y = P$,$x = \frac{1}{V}$,and $c = 0$,the slope $m$ is equal to $nRT$.Since $n$ and $R$ are constants,the slope $m$ is directly proportional to the temperature $T$ $(m \propto T)$.Given the condition $T_1 > T_2 > T_3$,it follows that the slopes must satisfy the order $m_1 > m_2 > m_3$.

The isotherms of an ideal gas at $T_1, T_2, T_3$ along with their slopes $(m)$ are shown in the graph. If $T_1 > T_2 > T_3$,then the correct order of slopes of these isotherms is:

Similar Questions

$A$ gas has a volume of $3.4 \ L$ at $298 \ K$. What is the final temperature if the volume of gas increases to $6.8 \ L$ (in $K$)?

$A$ certain mass of a gas occupies a volume of $250 \ mL$ at $2 \ atm$ pressure. Calculate the volume of the gas if the pressure is increased to $2.5 \ atm$ at a constant temperature. (in $mL$)

If $P, V, M, T,$ and $R$ represent pressure,volume,molar mass,temperature,and gas constant respectively,then the density of an ideal gas is given by:

At constant pressure,the volume of a fixed mass of an ideal gas is directly proportional to

The value of the universal gas constant $R$ is the same for all gases. What is its physical significance?

Vedclass Test Series

Exam Paper Generator

Online Exam Module