The kinetic energy of an electron is 4.55 tim | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Kinetic Energy $(KE) = 4.55 	imes 10^{-25} \ J$,mass of electron $(m) = 9.1 	imes 10^{-31} \ kg$,Planck's constant $(h) = 6.626 	imes 10

Vedclass · Accepted Answer

$7.25 	imes 10^{-7} \ m$

Vedclass · Answer

(A) Given: Kinetic Energy $(KE) = 4.55 	imes 10^{-25} \ J$,mass of electron $(m) = 9.1 	imes 10^{-31} \ kg$,Planck's constant $(h) = 6.626 	imes 10^{-34} \ J \ s$.Using the formula for kinetic energy: $KE = \frac{1}{2} mv^2$.$4.55 	imes 10^{-25} = \frac{1}{2} 	imes 9.1 	imes 10^{-31} 	imes v^2$.$v^2 = \frac{2 	imes 4.55 	imes 10^{-25}}{9.1 	imes 10^{-31}} = \frac{9.1 	imes 10^{-25}}{9.1 	imes 10^{-31}} = 10^6$.$v = 10^3 \ m \ s^{-1}$.Applying the de Broglie equation: $\lambda = \frac{h}{mv}$.$\lambda = \frac{6.626 	imes 10^{-34}}{9.1 	imes 10^{-31} 	imes 10^3} = \frac{6.626}{9.1} 	imes 10^{-6} \ m \approx 0.728 	imes 10^{-6} \ m = 7.28 	imes 10^{-7} \ m$.

The kinetic energy of an electron is $4.55 \times 10^{-25} \ J$. Find its wavelength.

Similar Questions

$A$ cricket ball of $0.5 \ kg$ is moving with a velocity of $100 \ m/s$. The wavelength associated with its motion is

State the de Broglie principle.

What is the de Broglie wavelength of a tennis ball weighing $66 \ g$ moving with a velocity of $10 \ m/s$?

If two particles $A$ and $B$ are moving with the same velocity,but the wavelength of $A$ is found to be double that of $B$. Which of the following statements is correct?

What will be the wavelength of a ball of mass $0.1 \,kg$ moving with a velocity of $10 \,m \,s^{-1}?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module