The kinetic energy of one mole of gas at 300 | vedclass

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Question

(A) The average kinetic energy of one mole of an ideal gas is given by the formula $E = \frac{3}{2}RT,$ where $R$ is the universal gas constant and $T

Vedclass · Accepted Answer

$1.33$

Vedclass · Answer

(A) The average kinetic energy of one mole of an ideal gas is given by the formula $E = \frac{3}{2}RT,$ where $R$ is the universal gas constant and $T$ is the absolute temperature in Kelvin.Since $R$ is a constant,the kinetic energy $E$ is directly proportional to the temperature $T$ $(E \propto T)$.Therefore,the ratio of kinetic energies at two different temperatures $T$ and $T'$ is given by $\frac{E'}{E} = \frac{T'}{T}.$Given $T = 300 \ K$ and $T' = 400 \ K,$$\frac{E'}{E} = \frac{400}{300} = \frac{4}{3} = 1.33.$

The kinetic energy of one mole of gas at $300 \ K$ temperature is $E.$ At $400 \ K$ temperature,the kinetic energy is $E'.$ The value of $E'/E$ is

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