The king,queen,and jack of clubs are removed from a deck of $52$ playing cards and then well shuffled. Now,one card is drawn at random from the remaining cards. What is the probability that the card is:
$(i)$ a club
$(ii)$ $10$ of hearts

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) $(i)$ Let $E_1$ be the event of getting a club.
Total cards remaining $= 52 - 3 = 49$.
Number of clubs remaining $= 13 - 3 = 10$.
$\therefore$ Probability $= \frac{10}{49}$.
$(ii)$ Let $E_2$ be the event of getting $10$ of hearts.
There is only one $10$ of hearts in the deck.
$\therefore$ Probability $= \frac{1}{49}$.

Explore More

Similar Questions

The probability of the month of April in a non-leap year having $5$ Sundays is .... . (in $/7$)

$A$ card is drawn from a deck of $52$ cards. The event $E$ is that the card is not an ace of hearts. The number of outcomes favourable to $E$ is

$A$ student says that if you throw a die,it will show up $1$ or not $1$. Therefore,the probability of getting $1$ and the probability of getting 'not $1$' each is equal to $\frac{1}{2}$. Is this correct? Give reasons.

$A$ card is drawn at random from a well-shuffled pack of $52$ cards. Find the probability that the card drawn is a queen.

Two balanced dice are rolled. Find the probability that the sum of numbers on two dice is a multiple of $5$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo