The laser in an audio compact disc uses light | vedclass

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Question

(D) The wavelength $\lambda$ is given as $7.8 	imes 10^2 \ nm$. Convert the wavelength to meters: $\lambda = 7.8 	imes 10^2 	imes 10^{-9} \ m = 7.8

Vedclass · Accepted Answer

$3.8 	imes 10^{14} \ s^{-1}$

Vedclass · Answer

(D) The wavelength $\lambda$ is given as $7.8 	imes 10^2 \ nm$. Convert the wavelength to meters: $\lambda = 7.8 	imes 10^2 	imes 10^{-9} \ m = 7.8 	imes 10^{-7} \ m$. The frequency $
u$ is calculated using the formula $
u = \frac{c}{\lambda}$,where $c = 3 	imes 10^8 \ m \ s^{-1}$ is the speed of light. $
u = \frac{3 	imes 10^8 \ m \ s^{-1}}{7.8 	imes 10^{-7} \ m} \approx 3.846 	imes 10^{14} \ s^{-1}$. Thus,the frequency is approximately $3.8 	imes 10^{14} \ s^{-1}$.

The laser in an audio compact disc uses light of wavelength $7.8 \times 10^2 \ nm$. What is the frequency of light emitted by the laser?

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