The least count of a stop watch is frac{1}{5} | vedclass

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(B) The least count of the stop watch is the absolute error in the measurement of the total time,so $\Delta t = \frac{1}{5} 	ext{ s} = 0.2 	ext{ s}$

Vedclass · Accepted Answer

$0.8$

Vedclass · Answer

(B) The least count of the stop watch is the absolute error in the measurement of the total time,so $\Delta t = \frac{1}{5} 	ext{ s} = 0.2 	ext{ s}$.The total time measured for $20$ oscillations is $t = 25 	ext{ s}$.The time period of one oscillation is $T = \frac{t}{20} = \frac{25}{20} = 1.25 	ext{ s}$.The absolute error in the time period $T$ is $\Delta T = \frac{\Delta t}{20} = \frac{0.2}{20} = 0.01 	ext{ s}$.The percentage error in the measurement of the time period is given by $\frac{\Delta T}{T} 	imes 100 \%$.Substituting the values: $\frac{0.01}{1.25} 	imes 100 \% = \frac{1}{125} 	imes 100 \% = 0.8 \%$.

The least count of a stop watch is $\frac{1}{5} \text{ s}$. The time of $20$ oscillations of a pendulum is measured to be $25 \text{ s}$. The maximum percentage error in the measurement of time will be .......... $\%$

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