The least number which when divided by 6, 9, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the least number that leaves a remainder of $2$ when divided by $6, 9, 12, 15,$ and $18$,we first find the Least Common Multiple $(LCM)$ o

Vedclass · Accepted Answer

$182$

Vedclass · Answer

(B) To find the least number that leaves a remainder of $2$ when divided by $6, 9, 12, 15,$ and $18$,we first find the Least Common Multiple $(LCM)$ of these numbers.Prime factorization:$6 = 2 	imes 3$$9 = 3^2$$12 = 2^2 	imes 3$$15 = 3 	imes 5$$18 = 2 	imes 3^2$$LCM = 2^2 	imes 3^2 	imes 5 = 4 	imes 9 	imes 5 = 180$.Since the number must leave a remainder of $2$ in each case,we add the remainder to the $LCM$.Required number $= LCM + 2 = 180 + 2 = 182$.

The least number which when divided by $6, 9, 12, 15, 18$ leaves the same remainder $2$ in each case is

Similar Questions

$3648.24 + 364.824 \div ? - 36.4824 = 3794.1696$

The last digit,that is,the digit in the unit's place of the number $[(57)^{25}-1]$ is

In a division sum,the divisor is $4$ times the quotient and twice the remainder. If $a$ and $b$ are respectively the divisor and the dividend,then

What is the least number that must be added to $4042$ to make it a perfect square?

$A$ two-digit number has $3$ as its unit's digit,and the sum of its digits is $\frac{1}{7}$ of the number itself. The number is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module