The length,breadth,and thickness of a block a | vedclass

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Question

(B) The volume $V$ of the block is calculated as $V = l 	imes b 	imes t$.Substituting the given values: $V = 12 \, cm 	imes 6 \, cm 	imes 2.45 \,

Vedclass · Accepted Answer

$2 	imes 10^2 \, cm^3$

Vedclass · Answer

(B) The volume $V$ of the block is calculated as $V = l 	imes b 	imes t$.Substituting the given values: $V = 12 \, cm 	imes 6 \, cm 	imes 2.45 \, cm = 176.4 \, cm^3$.According to the rules of significant figures for multiplication,the final result should have the same number of significant figures as the measurement with the least number of significant figures.The given values are $l = 12 \, cm$ ($2$ significant figures),$b = 6 \, cm$ ($1$ significant figure),and $t = 2.45 \, cm$ ($3$ significant figures).The least number of significant figures is $1$ (from the breadth $b = 6 \, cm$).Therefore,the result $176.4 \, cm^3$ must be rounded to one significant figure.Rounding $176.4$ to one significant figure gives $200 \, cm^3$,which is written as $2 	imes 10^2 \, cm^3$.

The length,breadth,and thickness of a block are given by $l = 12 \, cm$,$b = 6 \, cm$,and $t = 2.45 \, cm$. The volume of the block according to the rules of significant figures should be:

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