The length of a rectangular field is twice it | vedclass

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(A) Area of the rectangular field $= \frac{28000}{3500} = 8$ hectares.Since $1$ hectare $= 10000 	ext{ m}^2$,the area $= 8 	imes 10000 = 80000 	ext

Vedclass · Accepted Answer

$6000$

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(A) Area of the rectangular field $= \frac{28000}{3500} = 8$ hectares.Since $1$ hectare $= 10000 	ext{ m}^2$,the area $= 8 	imes 10000 = 80000 	ext{ m}^2$.Let the breadth be $x$ meters and the length be $2x$ meters.Area $= 	ext{Length} 	imes 	ext{Breadth} = 2x 	imes x = 2x^2$.$2x^2 = 80000 \implies x^2 = 40000 \implies x = 200 	ext{ m}$.Breadth $= 200 	ext{ m}$,Length $= 400 	ext{ m}$.Perimeter $= 2(	ext{Length} + 	ext{Breadth}) = 2(400 + 200) = 2(600) = 1200 	ext{ m}$.Cost of fencing $= 1200 	imes 5 = ₹ 6000$.

The length of a rectangular field is twice its breadth. If the rent of the field at ₹ $3500$ per hectare is ₹ $28000$,then find the cost of surrounding it with a fence at ₹ $5$ per meter (in ₹).

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