The length of a seconds pendulum at a height $h=2R$ from the earth's surface will be. (Given: $R =$ radius of earth and acceleration due to gravity at the surface of earth $g = \pi^{2} \ m/s^{2}$)

  • A
    $\frac{2}{9} \ m$
  • B
    $\frac{4}{9} \ m$
  • C
    $\frac{8}{9} \ m$
  • D
    $\frac{1}{9} \ m$

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