The length of the side of a cube is 1.2 times | vedclass

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(D) The length of the side of the cube is $l = 1.2 	imes 10^{-2} \ m$. The volume of a cube is given by $V = l^3$. $V = (1.2 	imes 10^{-2} \ m)^3 =

Vedclass · Accepted Answer

$1.7 	imes 10^{-6} \ m^3$

Vedclass · Answer

(D) The length of the side of the cube is $l = 1.2 	imes 10^{-2} \ m$. The volume of a cube is given by $V = l^3$. $V = (1.2 	imes 10^{-2} \ m)^3 = 1.728 	imes 10^{-6} \ m^3$. According to the rules of significant figures,the result of a multiplication or division should have the same number of significant figures as the measurement with the fewest significant figures. The given length $1.2 	imes 10^{-2} \ m$ has $2$ significant figures. Therefore,the volume should be rounded to $2$ significant figures. Rounding $1.728$ to $2$ significant figures gives $1.7$. Thus,the volume is $1.7 	imes 10^{-6} \ m^3$.

Column-$I$	Column-$II$
$(a)$ $0.007\ m^2$	$(p)$ $2$
$(b)$ $2.64 \times 10^{24}\ kg$	$(q)$ $1$
$(c)$ $0.0021\ g\ cm^{-3}$	$(r)$ $4$
$(d)$ $0.0006032\ J$	$(s)$ $3$

The length of the side of a cube is $1.2 \times 10^{-2} \ m$. Its volume up to correct significant figures is

Similar Questions

If $L = 2.331 \ cm$ and $B = 2.1 \ cm$,then $L + B =$ (in $cm$)

$A$ substance of mass $49.53 \ g$ occupies $1.5 \ cm^3$ of volume. The density of the substance (in $g \ cm^{-3}$) with the correct number of significant figures is:

Match the number of significant figures in the given column:

Column-$I$ Column-$II$

$(a)$ $0.007\ m^2$ $(p)$ $2$

$(b)$ $2.64 \times 10^{24}\ kg$ $(q)$ $1$

$(c)$ $0.0021\ g\ cm^{-3}$ $(r)$ $4$

$(d)$ $0.0006032\ J$ $(s)$ $3$

Three measurements are made as $18.425 \, cm$,$7.21 \, cm$,and $5.0 \, cm$. The addition should be written as ........ $cm$.

Which of the following measurements of length is the most precise? Why?
$(i) \ 2.0 \ cm$
$(ii) \ 2.00 \ cm$
$(iii) \ 2.000 \ cm$

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