The lengths of the two parallel sides of a trapezium are $16 \ m$ and $20 \ m$ respectively. If its height is $10 \ m$,its area in square metres is:

$A$ rectangular farm has to be fenced on one long side, one short side, and the diagonal. If the cost of fencing is ₹ $10$ per $m$, the area of the farm is $1200 \ m^2$, and the short side is $30 \ m$ long, how much would the job cost? (in ₹)

The base of a triangular field is three times its height. If the cost of cultivating the field at ₹ $36.72$ per hectare is ₹ $495.72$,then find its base and height.

$A$ rectangular field costs $Rs. 110$ for levelling at $50$ $paise$ per square metre. If the ratio of length to breadth is $11: 5$, find the length of the field (in $m$).

The area of an isosceles trapezium is $176 \, cm^2$ and the height is $2/11$ of the sum of its parallel sides. If the ratio of the length of the parallel sides is $4:7$,then the length of a diagonal (in $cm$) is

$A$ plot of land is in the shape of a right-angled isosceles triangle. The length of the hypotenuse is $50 \sqrt{2} \text{ m}$. The cost of fencing is ₹$3$ per metre. The total cost of fencing the plot will be