The lower reactivity of the chlorine atom in | vedclass

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(B) In $CH_2 = CH - Cl$,the lone pair of electrons on the chlorine atom is in conjugation with the $C = C$ double bond. This leads to the delocalizati

Vedclass · Accepted Answer

Resonance stabilization

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(B) In $CH_2 = CH - Cl$,the lone pair of electrons on the chlorine atom is in conjugation with the $C = C$ double bond. This leads to the delocalization of electrons,resulting in resonance structures. Due to this resonance,the $C - Cl$ bond acquires partial double bond character,which makes it stronger and shorter than a pure single bond. Consequently,the $C - Cl$ bond is difficult to break,leading to lower reactivity towards nucleophilic substitution reactions.

The lower reactivity of the chlorine atom in $CH_2 = CH - Cl$ is due to:

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