The logic circuit is shown below:ABY001010100 | vedclass

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(D) The circuit consists of two $AND$ gates and two $NOT$ gates. The inputs to the top $AND$ gate are $A$ and $\overline{B}$,so its output is $A\overl

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$XNOR$ Gate

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(D) The circuit consists of two $AND$ gates and two $NOT$ gates. The inputs to the top $AND$ gate are $A$ and $\overline{B}$,so its output is $A\overline{B}$.The inputs to the bottom $AND$ gate are $\overline{A}$ and $B$,so its output is $\overline{A}B$.These two outputs are fed into gate $G$. Let the output of $G$ be $Y$.If $G$ is an $XOR$ gate,$Y = A\overline{B} + \overline{A}B$.If $G$ is an $XNOR$ gate,$Y = \overline{A\overline{B} + \overline{A}B} = (A\overline{B} + \overline{A}B)' = A B + \overline{A}\overline{B}$.Let's check the truth table for $Y = AB + \overline{A}\overline{B}$:- For $A=0, B=0: Y = (0)(0) + (1)(1) = 1$.- For $A=0, B=1: Y = (0)(1) + (1)(0) = 0$.- For $A=1, B=0: Y = (1)(0) + (0)(1) = 0$.- For $A=1, B=1: Y = (1)(1) + (0)(0) = 1$.This matches the given truth table. Therefore,gate $G$ is an $XNOR$ gate.

$A$	$B$	$Y$
$0$	$0$	$1$
$0$	$1$	$0$
$1$	$0$	$0$
$1$	$1$	$1$

The logic circuit is shown below:
$A$ $B$ $Y$
$0$ $0$ $1$
$0$ $1$ $0$
$1$ $0$ $0$
$1$ $1$ $1$

To obtain the given truth table,which logic gate should be placed at $G$?

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The logic circuit is shown below:$A$$B$$Y$$0$$0$$1$$0$$1$$0$$1$$0$$0$$1$$1$$1$To obtain the given truth table,which logic gate should be placed at $G$?