The logical equivalent of $p \Leftrightarrow q$ is :-
- A$(p \wedge q) \vee (\neg p \wedge \neg q)$
- B$(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p)$
- C$(p \wedge q) \vee (q \Rightarrow p)$
- D$(p \wedge q) \Rightarrow (q \vee p)$
Explore More
Similar Questions
The negation of the statement "$12$ is a multiple of $3$ and $12$ is a multiple of $4$" is:
Easy
View SolutionThe truth values of $p \rightarrow r$ is $F$ and $p \leftrightarrow q$ is $F$. Then the truth values of $(\sim p \vee q) \rightarrow (p \vee \sim q)$ and $(p \wedge \sim q) \rightarrow (\sim p \wedge q)$ are respectively:
Write the negation of the following statement:
Both the diagonals of a rectangle have the same length.
Both the diagonals of a rectangle have the same length.
Easy
View SolutionIf the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is $False$, then the truth values of $p \to q$ and $q \to p$ are respectively......
DifficultMHT CET 2026
View SolutionThe number of ordered triplets of the truth values of $p, q$ and $r$ such that the truth value of the statement $(p \vee q) \wedge (p \vee r) \Rightarrow (q \vee r)$ is True,is equal to
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo