The lowest O-O bond length in the following m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the $O-O$ bond length, we look at the bond order of each species:$1$. For $O_2$, the bond order is $2.0$ (bond length $\approx 121

Vedclass · Accepted Answer

$O_2$

Vedclass · Answer

(B) To determine the $O-O$ bond length, we look at the bond order of each species:$1$. For $O_2$, the bond order is $2.0$ (bond length $\approx 121 	ext{ pm}$).$2$. For $O_3$, the bond order is $1.5$ (resonance hybrid, bond length $\approx 128 	ext{ pm}$).$3$. For $H_2O_2$, the bond order is $1.0$ (bond length $\approx 148 	ext{ pm}$).$4$. For $O_2F_2$, the bond order is $1.0$, but due to the high electronegativity of fluorine and repulsion between lone pairs, the $O-O$ bond is significantly elongated (bond length $\approx 149 	ext{ pm}$).Comparing these, $O_2$ has the highest bond order and therefore the shortest $O-O$ bond length.

The lowest $O-O$ bond length in the following molecules is:

Similar Questions

The $\sigma _{2s}^*$ molecular orbital has a nodal plane similar to which of the following orbitals?

Between $1s-1s$ and $1s-2s$ combinations,which one does not form a molecular orbital? Why?

The number of species from the following which are paramagnetic and with bond order equal to $1$ is:
$H_2, He_2^{+}, O_2^{+}, N_2^{2-}, O_2^{2-}, F_2, Ne_2^{+}, B_2$

The correct order of energy of $\sigma_{2p_z}$,$\pi_{2p_x}$,$\pi_{2p_y}$,$\pi_{2p_x}^$,$\pi_{2p_y}^$ and $\sigma_{2p_z}^*$ orbitals in $F_2$ is:

Among the following,the species with identical bond order are

Vedclass Test Series

Exam Paper Generator

Online Exam Module