The Lyman series of the hydrogen spectrum lie | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The spectral lines of the hydrogen atom are categorized into different series based on the energy level transitions of the electron.For the Lyman

Vedclass · Accepted Answer

Ultraviolet

Vedclass · Answer

(C) The spectral lines of the hydrogen atom are categorized into different series based on the energy level transitions of the electron.For the Lyman series,the electron transitions from any higher energy level $(n_2 = 2, 3, 4, ...)$ to the ground state $(n_1 = 1)$.The energy difference for these transitions is given by $\Delta E = 13.6 \left( \frac{1}{1^2} - \frac{1}{n_2^2} ight) 	ext{ eV}$.These transitions result in the emission of photons with high energy,which correspond to the ultraviolet $(UV)$ region of the electromagnetic spectrum.

List $I$ (Spectral Lines of Hydrogen for transitions from)	List $II$ (Wavelengths $(nm)$)
$A$. $n_2=3$ to $n_1=2$	$I$. $410.2$
$B$. $n_2=4$ to $n_1=2$	$II$. $434.1$
$C$. $n_2=5$ to $n_1=2$	$III$. $656.3$
$D$. $n_2=6$ to $n_1=2$	$IV$. $486.1$

The Lyman series of the hydrogen spectrum lies in which region?

Similar Questions

Which series is found in the visible light region?

In the spectrum of the hydrogen atom,the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is

$A$ hydrogen atom absorbs radiation of wavelength $975 \, \mathring{A}$ and transitions from the ground state to an excited state. How many spectral lines are possible in the emission spectrum?

In which of the following series does the $121.5 \ nm$ line of the spectrum of the hydrogen atom lie?

Vedclass Test Series

Exam Paper Generator

Online Exam Module