The magnetic field at a perpendicular distanc | vedclass

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Question

(B) The magnetic field '$B$' at a perpendicular distance '$r$' from a long straight wire carrying current '$I$' is given by the formula:$B = \frac{\mu

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$B/2$

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(B) The magnetic field '$B$' at a perpendicular distance '$r$' from a long straight wire carrying current '$I$' is given by the formula:$B = \frac{\mu_0 I}{2 \pi r}$From this expression, it is clear that the magnetic field is inversely proportional to the distance '$r$':$B \propto \frac{1}{r}$Let '$B_1$' be the magnetic field at distance '$r_1 = r$' and '$B_2$' be the magnetic field at distance '$r_2 = 2r$'.Then, $\frac{B_2}{B_1} = \frac{r_1}{r_2}$Substituting the values:$\frac{B_2}{B} = \frac{r}{2r} = \frac{1}{2}$Therefore, $B_2 = \frac{B}{2}$.

The magnetic field at a perpendicular distance '$r$' from a long straight wire carrying current '$I$' is '$B$'. The magnetic field at a perpendicular distance '$2r$' from the same wire is:

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