The magnetic field at the center of a circula | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic field $B$ at the center of a circular loop of radius $R$ carrying a current $I$ with $N$ turns is given by the formula: $B = \frac{\m

Vedclass · Accepted Answer

Radius of the loop

Vedclass · Answer

(B) The magnetic field $B$ at the center of a circular loop of radius $R$ carrying a current $I$ with $N$ turns is given by the formula: $B = \frac{\mu_0 N I}{2R}$.From this formula,it is clear that the magnetic field $B$ is directly proportional to the current $I$ and the number of turns $N$,and inversely proportional to the radius $R$ of the loop.Therefore,the magnetic field at the center is inversely proportional to the radius of the loop.

The magnetic field at the center of a circular loop carrying an electric current is inversely proportional to $..........$.

Similar Questions

$A$ soft iron bar is introduced inside a current-carrying solenoid. The magnetic field inside the solenoid:

Traditionally,which coloured insulation on wire is used for earthing?

Suggest one way of discriminating a wire carrying current from a wire carrying no current.

An alpha particle (positively charged particle) enters a magnetic field at a right angle to it,as shown in the figure. Explain the direction of the force acting on the alpha particle with the help of a relevant rule.

To find the direction of the magnetic field around a current-carrying conductor,we use Fleming's left-hand rule.

Vedclass Test Series

Exam Paper Generator

Online Exam Module