The magnetic field existing in a region is given by $\vec{B} = 0.2(1 + 2x) \hat{k} \text{ T}$. $A$ square loop of edge $50 \text{ cm}$ carrying $0.5 \text{ A}$ current is placed in the $x-y$ plane with its edges parallel to the $x-y$ axes,as shown in the figure. The magnitude of the net magnetic force experienced by the loop is . . . . . . $\text{mN}$.

The magnetic force between the wires as shown in the figure is:

$A$ single-turn current loop in the shape of a right-angled triangle with sides $5 \,cm, 12 \,cm, 13 \,cm$ carries a current of $2 \,A$. The loop is placed in a uniform magnetic field of magnitude $0.75 \,T$, whose direction is parallel to the current in the $13 \,cm$ side of the loop. The magnitude of the magnetic force on the $5 \,cm$ side is $\frac{x}{130} \,N$. The value of '$x$' is:

$A$ circular conducting loop of radius $R$ carries a current $I$. Another straight infinite conductor carrying current $I$ passes through the diameter of this loop as shown in the figure. The magnitude of the force exerted by the straight conductor on the loop is:

If a straight current-carrying wire of linear density $0.12 \ kg \ m^{-1}$ is suspended in mid-air by a uniform horizontal magnetic field of $0.5 \ T$ normal to the length of the wire,then the current through the wire is (Acceleration due to gravity $= 10 \ m \ s^{-2}$; Neglect earth's magnetic field) (in $A$)

Two long and parallel straight wires $A$ and $B$ carrying currents of $8.0 \, A$ and $5.0 \, A$ in the same direction are separated by a distance of $4.0 \, cm$. Estimate the force on a $10 \, cm$ section of wire $A$.