The magnetic moment of a short magnet is 16 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Magnetic moment $M = 16 \ Am^2$,distance $r = 20 \ cm = 0.2 \ m$. The constant $\frac{\mu_0}{4\pi} = 10^{-7} \ T \cdot m/A$. For an axial p

Vedclass · Accepted Answer

$4 	imes 10^{-4} \ T$ and $2 	imes 10^{-4} \ T$

Vedclass · Answer

(C) Given: Magnetic moment $M = 16 \ Am^2$,distance $r = 20 \ cm = 0.2 \ m$. The constant $\frac{\mu_0}{4\pi} = 10^{-7} \ T \cdot m/A$. For an axial point: $B_{	ext{axial}} = \frac{\mu_0}{4\pi} \frac{2M}{r^3} = 10^{-7} 	imes \frac{2 	imes 16}{(0.2)^3} = 10^{-7} 	imes \frac{32}{0.008} = 10^{-7} 	imes 4000 = 4 	imes 10^{-4} \ T$. For an equatorial point: $B_{	ext{equatorial}} = \frac{\mu_0}{4\pi} \frac{M}{r^3} = 10^{-7} 	imes \frac{16}{(0.2)^3} = 10^{-7} 	imes \frac{16}{0.008} = 10^{-7} 	imes 2000 = 2 	imes 10^{-4} \ T$. Thus,the values are $4 	imes 10^{-4} \ T$ and $2 	imes 10^{-4} \ T$.

The magnetic moment of a short magnet is $16 \ Am^2$. The magnetic induction at a point $20 \ cm$ away from its midpoint on $(i)$ axial point and $(ii)$ equatorial point respectively,will be:

Similar Questions

$A$ magnetic needle suspended parallel to a magnetic field requires $\sqrt{3} \, J$ of work to turn it through $60^{\circ}$. The torque needed to maintain the needle in this position will be.....

The effect due to a uniform magnetic field on a freely suspended magnetic needle is as follows:

The intensity of the magnetic field is $H$ and the magnetic moment of the magnet is $M$. The maximum potential energy is $..... MH$.

Points $A$ and $B$ are situated along the extended axis of a $2 \ cm$ long bar magnet at distances $x$ and $2x$ $cm$ respectively from the nearer pole. The ratio of the magnetic field at $A$ and $B$ will be:

The magnetic moment of a bar magnet is $0.5 \text{ A m}^2$. It is suspended in a uniform magnetic field of $8 \times 10^{-2} \text{ T}$. The work done in rotating it from its most stable to most unstable position is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module