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(A) According to Bohr's theory, the orbital angular momentum $L$ of an electron in the $n^{th}$ orbit is given by $L = \frac{nh}{2\pi}$.The magnetic m

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$n$

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(A) According to Bohr's theory, the orbital angular momentum $L$ of an electron in the $n^{th}$ orbit is given by $L = \frac{nh}{2\pi}$.The magnetic moment $\mu_l$ associated with the orbital motion of an electron is given by $\mu_l = \frac{e}{2m} L$.Substituting the value of $L$, we get $\mu_l = \frac{e}{2m} \left( \frac{nh}{2\pi} \right)$.Since $e$, $m$, $h$, and $\pi$ are constants, we can see that $\mu_l \propto n$.Therefore, the magnetic moment is proportional to the principal quantum number $n$.

The magnetic moment of an electron due to its orbital motion is proportional to ($n$ = principal quantum number).

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