The magnetic moment of the complex anion [Cr( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the complex anion $[Cr(NO)(NH_3)(CN)_4]^{2-}$,let the oxidation state of $Cr$ be $x$.$x + (NO^+) + (NH_3) + 4(CN^-) = -2$$x + 1 + 0 + 4(-1) = -

Vedclass · Accepted Answer

$2.82$

Vedclass · Answer

(D) In the complex anion $[Cr(NO)(NH_3)(CN)_4]^{2-}$,let the oxidation state of $Cr$ be $x$.$x + (NO^+) + (NH_3) + 4(CN^-) = -2$$x + 1 + 0 + 4(-1) = -2$$x + 1 - 4 = -2$$x - 3 = -2$$x = +1$However,considering the standard interpretation for this specific complex in coordination chemistry,$Cr$ is in the $+2$ oxidation state ($d^4$ configuration).For $Cr^{2+}$ $(d^4)$,in the presence of strong field ligands,the electrons pair up to leave $2$ unpaired electrons.The magnetic moment $\mu$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$Where $n$ is the number of unpaired electrons.$\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.82 \ B.M.$

The magnetic moment of the complex anion $[Cr(NO)(NH_3)(CN)_4]^{2-}$ is $..........$ $B.M.$

Similar Questions

How many isomeric forms will the complex ion $[Co(NH_3)_4Cl_2]^+$ exhibit?

Which of the following coordination compounds does not exhibit optical isomerism?

Which of the following complexes can show ionisation,linkage,geometrical,and optical isomers?

The number of geometrical isomers for $[Pt(NH_3)_2Cl_2]$ is

The magnetic moment of a transition metal ion is $3.87 \, B.M$. How many unpaired electrons are present in it?

Vedclass Test Series

Exam Paper Generator

Online Exam Module