(B) In a tangent galvanometer,the magnetic field $B$ produced by the coil is related to the horizontal component of the Earth's magnetic field $B_H$ a

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(B) In a tangent galvanometer,the magnetic field $B$ produced by the coil is related to the horizontal component of the Earth's magnetic field $B_H$ and the deflection angle $\theta$ by the formula: $B = B_H \tan \theta$ Given: $B_H = 0.34 \times 10^{-4} \, T$ $\theta = 30^\circ$ Substituting the values: $B = (0.34 \times 10^{-4}) \times \tan 30^\circ$ Since $\tan 30^\circ = \frac{1}{\sqrt{3}} \approx 0.577$: $B = 0.34 \times 10^{-4} \times 0.577$ $B \approx 0.196 \times 10^{-4} \, T$ $B = 1.96 \times 10^{-5} \, T$

Class 12 Physics Magnetism and Matter Magnetic Equipment's (Tangent galvanometer, Vibration magnetometer and Neutral point)

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The magnetic needle of a tangent galvanometer is deflected at an angle $30^\circ$ due to a magnet. The horizontal component of Earth's magnetic field $0.34 \times 10^{-4} \, T$ is along the plane of the coil. The magnetic intensity is

AIIMS 2000 All AIIMS

A
$1.96 \times 10^{-4} \, T$
B
$1.96 \times 10^{-5} \, T$
C
$1.96 \times 10^{4} \, T$
D
$1.96 \times 10^{5} \, T$

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Magnetic Equipment's (Tangent galvanometer, Vibration magnetometer and Neutral point)

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MediumAIIMS 2000

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MediumAP EAMCET 2022

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The magnetic needle of a tangent galvanometer is deflected at an angle $30^\circ$ due to a magnet. The horizontal component of Earth's magnetic field $0.34 \times 10^{-4} \, T$ is along the plane of the coil. The magnetic intensity is

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