(D) The electronic configuration of sodium ($Na$,atomic number $11$) is $1s^2 2s^2 2p^6 3s^1$. The valence electron is in the $3s$ orbital. For the $3

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(D) The electronic configuration of sodium ($Na$,atomic number $11$) is $1s^2 2s^2 2p^6 3s^1$. The valence electron is in the $3s$ orbital. For the $3s$ orbital,the principal quantum number $n = 3$,the azimuthal quantum number $l = 0$,and the magnetic quantum number $m_l = 0$. Thus,the magnetic quantum number for the valence electron is $0$.