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Question

(C) The absolute permeability $\mu$ is given by the formula: $\mu = \mu_0(1 + \chi_m)$,where $\mu_0$ is the permeability of free space and $\chi_m$ is

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) The absolute permeability $\mu$ is given by the formula: $\mu = \mu_0(1 + \chi_m)$,where $\mu_0$ is the permeability of free space and $\chi_m$ is the magnetic susceptibility.Given: $\mu_0 = 4\pi 	imes 10^{-7} 	ext{ H/m}$ and $\chi_m = 499$.Substituting the values:$\mu = 4\pi 	imes 10^{-7} 	imes (1 + 499)$$\mu = 4\pi 	imes 10^{-7} 	imes 500$$\mu = 4\pi 	imes 10^{-7} 	imes 5 	imes 10^2$$\mu = 20\pi 	imes 10^{-5} 	ext{ H/m}$$\mu = 2\pi 	imes 10^{-4} 	ext{ H/m}$.Comparing this with the given format $....\pi 	imes 10^{-4} 	ext{ H/m}$,the missing value is $2$.

The magnetic susceptibility of a material of a rod is $499$. Permeability in vacuum is $4\pi \times 10^{-7} \text{ H/m}$. Absolute permeability of the material of the rod is $....\pi \times 10^{-4} \text{ H/m}$.

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