The major aromatic product C in the following | vedclass

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(B) $1$. The reaction of $2$-methyl-$2H$-chromene with excess $HBr$ under heating leads to the cleavage of the ether ring. The $C-O$ bond breaks,and $

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(B) $1$. The reaction of $2$-methyl-$2H$-chromene with excess $HBr$ under heating leads to the cleavage of the ether ring. The $C-O$ bond breaks,and $HBr$ adds across the double bond and the ring-opened position,resulting in a phenolic compound with a dibromoalkyl side chain: $2-(3,5-dibromopentyl)phenol$ (or similar depending on regioselectivity,but the provided solution image shows the specific transformation).$2$. Treatment with alcoholic $KOH$ followed by $H^+$ causes dehydrohalogenation,forming a conjugated diene side chain attached to the phenol ring: $2-(penta-1,3-dienyl)phenol$.$3$. Finally,reductive ozonolysis $(O_3, Zn/H_2O)$ cleaves the double bonds in the side chain. The terminal double bond yields formaldehyde $(HCHO)$,the internal double bond yields glyoxal $(CHO-CHO)$,and the side chain attached to the benzene ring yields salicylaldehyde $(2-hydroxybenzaldehyde)$.$4$. Among the options,the major aromatic product $C$ is salicylaldehyde.

The major aromatic product $C$ in the following reaction sequence will be :

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