The major product B in the following reaction | vedclass

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(A) The reaction sequence is as follows: $1.$ Hofmann Bromamide Degradation: $CH_3-CH_2-CH(CH_3)-CONH_2 \xrightarrow{Br_2/KOH, \Delta} CH_3-CH_2-CH(CH

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$CH_3-CH_2-CH=CH_2$

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(A) The reaction sequence is as follows: $1.$ Hofmann Bromamide Degradation: $CH_3-CH_2-CH(CH_3)-CONH_2 \xrightarrow{Br_2/KOH, \Delta} CH_3-CH_2-CH(CH_3)-NH_2$ (sec-butylamine). $2.$ Hofmann Elimination: $CH_3-CH_2-CH(CH_3)-NH_2$ $\xrightarrow{CH_3I (excess)} CH_3-CH_2-CH(CH_3)-N^{+}(CH_3)_3 I^{-}$ $\xrightarrow{AgOH, \Delta} CH_3-CH_2-CH=CH_2$ ($1$-butene). According to Hofmann's rule,the less substituted alkene is the major product in Hofmann elimination.

The major product $B$ in the following reaction sequence is:
$CH_3-CH_2-CH(CH_3)-CONH_2$ $\xrightarrow{Br_2/KOH, \Delta} (A)$ $\xrightarrow{(1) CH_3I (excess), (2) AgOH/\Delta} (B)$

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The major product $B$ in the following reaction sequence is: $CH_3-CH_2-CH(CH_3)-CONH_2$ $\xrightarrow{Br_2/KOH, \Delta} (A)$ $\xrightarrow{(1) CH_3I (excess), (2) AgOH/\Delta} (B)$