The major product (P) formed in the below rea | vedclass

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(C) The reaction is an oxymercuration-demercuration of an alkene. $1$. In the first step,$Hg(OAc)_2$ in aqueous $THF$ reacts with the alkene to form a

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$1-$Methylcyclohexanol

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(C) The reaction is an oxymercuration-demercuration of an alkene. $1$. In the first step,$Hg(OAc)_2$ in aqueous $THF$ reacts with the alkene to form an organomercurial intermediate via an electrophilic addition of $Hg(OAc)^+$ followed by the attack of water. $2$. In the second step,$NaBH_4$ reduces the $C-Hg$ bond to a $C-H$ bond,resulting in the Markovnikov addition of water across the double bond. $3$. For methylenecyclohexane,the addition of water follows Markovnikov's rule,where the $OH$ group attaches to the more substituted carbon (the tertiary carbon of the ring). $4$. Thus,the product formed is $1$-methylcyclohexanol. Hence,option $(C)$ is the correct answer.

The major product $(P)$ formed in the below reaction is:
$CH_2$ attached to a cyclohexane ring $\xrightarrow[(ii) NaBH_4, OH^-]{(i) Hg(OAc)_2, H_2O-THF} P?$

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The major product $(P)$ formed in the below reaction is:$CH_2$ attached to a cyclohexane ring $\xrightarrow[(ii) NaBH_4, OH^-]{(i) Hg(OAc)_2, H_2O-THF} P?$