The major product formed in the following rea | vedclass

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(D) The reaction involves the bromination of isobutane $(CH_3-CH(CH_3)-CH_3)$ using $CH_3OBr$ as a brominating agent,which proceeds via a free radical

Vedclass · Accepted Answer

$CH_3-C(OCH_3)(CH_3)-CH_3$

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(D) The reaction involves the bromination of isobutane $(CH_3-CH(CH_3)-CH_3)$ using $CH_3OBr$ as a brominating agent,which proceeds via a free radical mechanism. The tertiary hydrogen atom is the most reactive,leading to the formation of tert-butyl bromide $(CH_3-C(CH_3)_2-Br)$ as the intermediate. Subsequently,the tert-butyl bromide undergoes $S_N1$ solvolysis in the presence of the solvent methanol $(CH_3OH)$ to form the major product,$2$-methoxy-$2$-methylpropane $(CH_3-C(OCH_3)(CH_3)-CH_3)$.

The major product formed in the following reaction is:
$CH_3-CH(CH_3)-CH_3 \xrightarrow[CH_3OH]{CH_3OBr}$

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The major product formed in the following reaction is: $CH_3-CH(CH_3)-CH_3 \xrightarrow[CH_3OH]{CH_3OBr}$