The major product formed in the following rea | vedclass

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(A) $1$. Propene undergoes anti-Markovnikov addition with $HBr$ in the presence of peroxide to form $1-$bromopropane: $CH_3-CH=CH_2 + HBr \xrightarrow

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$3-$Hexanone

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(A) $1$. Propene undergoes anti-Markovnikov addition with $HBr$ in the presence of peroxide to form $1-$bromopropane: $CH_3-CH=CH_2 + HBr \xrightarrow{	ext{peroxide}} CH_3-CH_2-CH_2Br$.$2$. $1-$bromopropane reacts with $Mg$ in the presence of dry ether to form the Grignard reagent,propylmagnesium bromide: $CH_3-CH_2-CH_2Br + Mg \xrightarrow{	ext{dry ether}} CH_3-CH_2-CH_2MgBr$.$3$. Propanal $(CH_3-CH_2-CHO)$ undergoes nucleophilic addition with propylmagnesium bromide followed by hydrolysis to form hexan$-3-$ol: $CH_3-CH_2-CHO + CH_3-CH_2-CH_2MgBr ightarrow CH_3-CH_2-CH(OH)-CH_2-CH_2-CH_3$.$4$. Hexan$-3-$ol on oxidation with $CrO_3$ forms hexan$-3-$one: $CH_3-CH_2-CH(OH)-CH_2-CH_2-CH_3 \xrightarrow{CrO_3} CH_3-CH_2-CO-CH_2-CH_2-CH_3$.

The major product formed in the following reaction sequence is $CH_3-CH=CH_2$ $\xrightarrow[\substack{(iii) \ CH_3-CH_2-CHO \\ (iv) \ CrO_3}]{\substack{(i) \ HBr, \text{ peroxide} \\ (ii) \ Mg}}$

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