The major product in the following reaction s | vedclass

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(B) The reaction sequence is as follows:$1$. Acetylation of aniline with $(CH_3CO)_2O$ and pyridine protects the $-NH_2$ group,forming acetanilide.$2$

Vedclass · Accepted Answer

$1-$bromo$-4-$chlorobenzene

Vedclass · Answer

(B) The reaction sequence is as follows:$1$. Acetylation of aniline with $(CH_3CO)_2O$ and pyridine protects the $-NH_2$ group,forming acetanilide.$2$. Electrophilic aromatic substitution with $Br_2$ in $CH_3CO_2H$ occurs at the para-position due to the steric hindrance of the $-NHCOCH_3$ group,yielding $p$-bromoacetanilide.$3$. Hydrolysis with $NaOH(aq)$ removes the acetyl group to regenerate $p$-bromoaniline.$4$. Diazotization with $HNO_2$ at $0-5 \ ^\circ C$ converts the $-NH_2$ group into a diazonium salt,$-N_2^+Cl^-$.$5$. The Sandmeyer reaction with $CuCl/HCl$ replaces the diazonium group with a chlorine atom,resulting in $1$-bromo-$4$-chlorobenzene.

The major product in the following reaction sequence is:

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