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(A) The reaction is Oxymercuration-Demercuration of $3,3-$dimethylbut$-1-$ene.This reaction involves the addition of $H_2O$ across the double bond fol

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$3,3-$dimethylbutan$-2-$ol

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(A) The reaction is Oxymercuration-Demercuration of $3,3-$dimethylbut$-1-$ene.This reaction involves the addition of $H_2O$ across the double bond following Markovnikov's rule.An important feature of this reaction is that it proceeds without carbocation rearrangement.Therefore,the $OH$ group attaches to the more substituted carbon ($C$-$2$) and the $H$ atom attaches to the less substituted carbon ($C$-$1$),resulting in $3,3-$dimethylbutan$-2-$ol as the major product.

The major product in the following reaction is:

Similar Questions

The major product of the following reaction is:

$HCl$ does not show the peroxide effect because the reaction mechanism involves the following steps:
$CH_3-CH=CH_2 + \dot{X} \to CH_3-\dot{C}H-CH_2X$ $(I)$
$CH_3-\dot{C}H-CH_2X + HX \to CH_3-CH_2-CH_2X + \dot{X}$ $(II)$
Why does $HCl$ fail to undergo this reaction?

Consider the following reaction:
$Alkene (A) \xrightarrow{KMnO_4, \Delta} CH_3CH_2COCH_3 + CH_3CH_2CH_2CH_2COOH$
$A$ is:

The number of alkenyl groups possible from $C_{4}H_{7}$ are

$CH_3-CH_2-CH_2-Br$ $\xrightarrow{\text{alk. KOH}} A$ $\xrightarrow[(ii) H_2O_2/OH^{-}]{(i) BD_3/THF} B$; $B$ is:

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