The major product of the following reaction i | vedclass

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(A) $DIBAL-H$ (diisobutylaluminium hydride) is a selective reducing agent. At low temperatures $(-78^{\circ}C)$,it reduces both ester $(-COOEt)$ and n

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An aldehyde at both ends of the chain.

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(A) $DIBAL-H$ (diisobutylaluminium hydride) is a selective reducing agent. At low temperatures $(-78^{\circ}C)$,it reduces both ester $(-COOEt)$ and nitrile $(-CN)$ functional groups to aldehydes. Since the reaction uses excess $DIBAL-H$ followed by acidic workup $(H_3O^+)$,both functional groups are converted into aldehyde groups $(-CHO)$. The final product is a dialdehyde.

The major product of the following reaction is:

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The major product of the following reaction is:

Butanone reacts with methyl magnesium bromide to form an addition product $(Z)$. On hydrolysis,$(Z)$ gives:

$Ph-CH_3$ $\xrightarrow{CrO_2Cl_2} (A)$ $\xrightarrow{conc. KOH} Ph-CH_2OH + (B)$
Product $(B)$ of the above reaction is:

Aldol condensation will not take place in

The rearrangement of an oxime to an amide in the presence of a strong acid is called:

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The major product of the following reaction is:

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The major product of the following reaction is:

Butanone reacts with methyl magnesium bromide to form an addition product $(Z)$. On hydrolysis,$(Z)$ gives:

$Ph-CH_3$ $\xrightarrow{CrO_2Cl_2} (A)$ $\xrightarrow{conc. KOH} Ph-CH_2OH + (B)$Product $(B)$ of the above reaction is:

Aldol condensation will not take place in

The rearrangement of an oxime to an amide in the presence of a strong acid is called:

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$Ph-CH_3$ $\xrightarrow{CrO_2Cl_2} (A)$ $\xrightarrow{conc. KOH} Ph-CH_2OH + (B)$
Product $(B)$ of the above reaction is: