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(C) The reaction involves the nucleophilic substitution of a primary alkyl halide in the presence of $NaCN$ and $DMF$ (a polar aprotic solvent), which

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$2-$($3$-iodophenyl)acetonitrile

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(C) The reaction involves the nucleophilic substitution of a primary alkyl halide in the presence of $NaCN$ and $DMF$ (a polar aprotic solvent), which favors the $S_{N}2$ mechanism.The substrate contains two halogen atoms: an iodine atom directly attached to the benzene ring (aryl iodide) and a chlorine atom attached to a benzylic carbon (benzylic chloride).$1$. The $C-I$ bond attached to the benzene ring has partial double-bond character due to resonance, making it very resistant to nucleophilic substitution.$2$. The benzylic $C-Cl$ bond is highly reactive towards $S_{N}2$ substitution because the transition state is stabilized by the adjacent benzene ring.Therefore, the $CN^-$ nucleophile selectively attacks the benzylic carbon, displacing the $Cl^-$ ion to form $2-(3-iodophenyl)acetonitrile$ as the major product.

The major product of the following reaction is:

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