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Question

(D) The reaction is a dehydrohalogenation reaction involving the elimination of two molecules of $HBr$ from $2,4$-dibromohexane using alcoholic $KOH$

Vedclass · Accepted Answer

$CH_3-CH=CH-CH=CH-CH_3$

Vedclass · Answer

(D) The reaction is a dehydrohalogenation reaction involving the elimination of two molecules of $HBr$ from $2,4$-dibromohexane using alcoholic $KOH$ and heat.According to $Saytzeff's$ rule,the most stable alkene is formed as the major product.In this case,the formation of $2,4$-hexadiene $(CH_3-CH=CH-CH=CH-CH_3)$ is favored because it is a conjugated diene,which provides extra stability due to resonance compared to isolated or cumulated dienes.

The major product of the following reaction is: $CH_3-CH(Br)-CH_2-CH(Br)-CH_2-CH_3 \xrightarrow[heat]{KOH, CH_3OH}$

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