The major product of the following reaction i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of $1$-methylcyclohex-$1$-ene with $Br_2$ in the presence of light $(h
u)$ is a free radical substitution reaction (allylic brominat

Vedclass · Accepted Answer

$1-$bromo$-1-$methylcyclohex$-2-$ene

Vedclass · Answer

(B) The reaction of $1$-methylcyclohex-$1$-ene with $Br_2$ in the presence of light $(h
u)$ is a free radical substitution reaction (allylic bromination).In this reaction,the bromine radical $(Br^\bullet)$ abstracts a hydrogen atom from the allylic position.The most stable free radical formed is the tertiary $(3^\circ)$ allylic radical at the $C-1$ position.This radical then reacts with $Br_2$ to form $1$-bromo-$1$-methylcyclohex-$2$-ene as the major product.

The major product of the following reaction is

Similar Questions

The reaction is $2\text{-methylbuta-1,3-diene} + HBr \rightarrow \text{products}$. Identify the correct statement regarding the products of this reaction.

In the following sequence of reactions,the alkene affords the compound $B$.
$CH_3-CH=CH-CH_3$ $\xrightarrow{O_3} A$ $\xrightarrow[Zn]{H_2O} B$
The compound $B$ is:

The reaction of a hydrocarbon with hypochlorous acid $(HOCl)$ gives $2-$chloroethanol. The hydrocarbon is .........

The product of the following reaction is:

Identify products $[A]$,$[B]$,and $[C]$ in the following reaction sequence:
$CH_3-C \equiv CH$ $\xrightarrow{H_2, Pd/C} [A]$ $\xrightarrow[(ii) Zn, H_2O]{(i) O_3} [B] + [C]$

Vedclass Test Series

Exam Paper Generator

Online Exam Module