The major product of the following reaction i | vedclass

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Question

(A) Step $1$: Treatment with aqueous $KOH$ performs nucleophilic substitution of the primary alkyl bromide to form a primary alcohol,$3-(3-bromophenyl

Vedclass · Accepted Answer

$6-$bromo$-1-$indanone

Vedclass · Answer

(A) Step $1$: Treatment with aqueous $KOH$ performs nucleophilic substitution of the primary alkyl bromide to form a primary alcohol,$3-(3-bromophenyl)propan-1-ol$.Step $2$: Oxidation with $CrO_3/H^+$ (Jones reagent) converts the primary alcohol into a carboxylic acid,$3-(3-bromophenyl)propanoic acid$.Step $3$: Intramolecular Friedel-Crafts acylation using $H_2SO_4/\Delta$ leads to cyclization. The carboxylic acid group attacks the ortho position relative to the alkyl chain. Since the meta-bromo group directs the cyclization,the product formed is $6-bromo-1-indanone$.

The major product of the following reaction is:

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