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(D) The reaction proceeds as follows:$1$. Treatment of the primary amine with $NaNO_2/H^+$ leads to the formation of a diazonium salt,which is unstabl

Vedclass · Accepted Answer

$5-$hydroxy$-1-$indanone

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(D) The reaction proceeds as follows:$1$. Treatment of the primary amine with $NaNO_2/H^+$ leads to the formation of a diazonium salt,which is unstable and undergoes hydrolysis to form a primary alcohol: $Ar-(CH_2)_3-OH$.$2$. Oxidation with $CrO_3/H^+$ (Jones reagent) oxidizes the primary alcohol to a carboxylic acid: $Ar-(CH_2)_2-COOH$.$3$. Treatment with conc. $H_2SO_4$ and heat causes an intramolecular Friedel-Crafts acylation. During this process,the ester group (acetoxy) is hydrolyzed to a phenolic $-OH$ group under acidic conditions. The resulting carboxylic acid cyclizes onto the benzene ring to form a five-membered ketone ring,yielding $5-hydroxy-1-indanone$.

The major product of the following reaction is:

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