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(C) The reaction involves the cleavage of ethers with excess $HI$. $1$. The oxygen atoms are protonated by $H^+$. $2$. The methoxy group attached to t

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(C) The reaction involves the cleavage of ethers with excess $HI$. $1$. The oxygen atoms are protonated by $H^+$. $2$. The methoxy group attached to the benzene ring is cleaved to form a phenol and $CH_3I$. $3$. The other ether linkage is cleaved by $I^-$ via an $S_N1$ or $S_N2$ mechanism (depending on the stability of the carbocation) to form an alcohol and an alkyl iodide. $4$. In this specific case,the benzylic position is stabilized by the cyano group,allowing the formation of the iodo product at that position. $5$. The final product is $3$-hydroxyphenyl-cyano-iodomethane.

The major product of the following reaction is

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