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(C) The reaction sequence is as follows:$1$. Electrophilic aromatic substitution of $p$-cresol with $Br_2$ gives $2$-bromo-$4$-methylphenol.$2$. Treat

Vedclass · Accepted Answer

$3-$bromo$-4-$methoxyphenylacetic acid

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(C) The reaction sequence is as follows:$1$. Electrophilic aromatic substitution of $p$-cresol with $Br_2$ gives $2$-bromo-$4$-methylphenol.$2$. Treatment with $NaOH$ forms the sodium phenoxide salt.$3$. Williamson's ether synthesis with $CH_3I$ yields $2$-bromo-$1$-methoxy-$4$-methylbenzene.$4$. Free radical bromination of the methyl group with $Br_2/h
u$ gives $2$-bromo-$1$-methoxy-$4$-(bromomethyl)benzene.$5$. Nucleophilic substitution with $KCN$ replaces the benzylic bromine with a cyano group to form $2$-bromo-$1$-methoxy-$4$-(cyanomethyl)benzene.$6$. Acidic hydrolysis of the cyanide group $(H_3O^+, \Delta)$ yields the final product,$2$-bromo-$4$-methoxyphenylacetic acid.

The major product of the following reaction sequence is

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