The major product of the reaction is

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is a Friedel-Crafts acylation of a substituted benzene ring. The substrate is $1,1,3$-trimethylindane (or a similar derivative). The

Vedclass · Accepted Answer

Vedclass · Answer

(A) The reaction is a Friedel-Crafts acylation of a substituted benzene ring. The substrate is $1,1,3$-trimethylindane (or a similar derivative). The incoming electrophile is the acetyl cation,$CH_3CO^+$,generated from $CH_3COCl$ and $AlCl_3$. The substitution occurs at the position that is most activated and least sterically hindered. In the given structure,the position ortho to the alkyl group on the benzene ring is the most favorable site for electrophilic aromatic substitution due to the activating effect of the alkyl groups and the relative lack of steric hindrance compared to other positions. Therefore,the acetyl group attaches to the carbon atom that is ortho to the $tert$-butyl group and meta to the other alkyl group,which corresponds to the structure shown in option $A$.

Similar Questions

When comparing the hydrogenation of benzene with that of a hypothetical $1,3,5-$cyclohexatriene,benzene .................... than the cyclohexatriene.

The total number of benzene derivatives with the molecular formula $C_6H_3Cl_3$ is:

Friedel-Crafts reaction using $MeCl$ and anhydrous $AlCl_3$ will take place most efficiently with

Draw the structure of the compound having molecular formula $C_7H_8$ and determine the number of $\sigma$ and $\pi$ bonds.

The reaction of benzene with isobutylene in the presence of $H_2SO_4$ gives:

Vedclass Test Series

Exam Paper Generator

Online Exam Module