The major product of the reaction of $2-$butene with cold alkaline $KMnO_4$ is:

  • A
    but$-2-$ene$-2,3-$diol
    Option A
  • B
    butane$-2,3-$dione
    Option B
  • C
    butanoic acid
    Option C
  • D
    butane$-2,3-$diol
    Option D

Explore More

Similar Questions

The reaction of propene with $HOCl$ $(Cl_2 + H_2O)$ proceeds through the intermediate $:$

The correct statement$(s)$ for the following addition reactions is(are):
$(i)$ $trans-but-2-ene \xrightarrow{Br_2/CHCl_3} M \text{ and } N$
(ii) $cis-but-2-ene \xrightarrow{Br_2/CHCl_3} O \text{ and } P$
[$A$] ($M$ and $O$) and ($N$ and $P$) are two pairs of diastereomers
[$B$] Bromination proceeds through trans-addition in both the reactions
[$C$] $O$ and $P$ are identical molecules
[$D$] ($M$ and $O$) and ($N$ and $P$) are two pairs of enantiomers

Which of the following compounds is formed as the major product in the following reaction?
$2-\text{methylbut-}2-\text{ene} \xrightarrow[\text{Peroxide}]{HBr} \text{Product}$

$A$ compound $X$ absorbs $2$ moles of hydrogen and $X$ upon oxidation with $KMnO_4 \mid H^{+}$ gives the products shown below:
$CH_3-CO-CH_3$,$CH_3-COOH$ and $CH_3-CO-CH_2-CH_2-COOH$.
The total number of $\sigma$ bonds present in the compound $X$ is . . . . . .

$X$ in the above reaction is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo