The major product ‘A’ in the given reaction i | vedclass

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(D) The reaction between benzaldehyde and acetophenone in the presence of a dilute base $(OH^-)$ is a Claisen-Schmidt condensation reaction.$1$. Aceto

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(D) The reaction between benzaldehyde and acetophenone in the presence of a dilute base $(OH^-)$ is a Claisen-Schmidt condensation reaction.$1$. Acetophenone acts as the nucleophile because it has $\alpha$-hydrogens, which are removed by the base to form an enolate ion.$2$. The enolate ion attacks the carbonyl carbon of benzaldehyde to form a $\beta$-hydroxy ketone.$3$. The $\beta$-hydroxy ketone undergoes dehydration (loss of $H_2O$) to form an $\alpha, \beta$-unsaturated ketone, which is the stable major product.$4$. The product is $1,3-	ext{diphenylprop-2-en-1-one}$ (also known as chalcone), represented by option $D$.

The major product ‘$A$’ in the given reaction is:
$\text{Benzaldehyde} + \text{Acetophenone} \xrightarrow[293 \text{ K}]{OH^-} \text{'A' (Major product)}$

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The major product ‘$A$’ in the given reaction is:$\text{Benzaldehyde} + \text{Acetophenone} \xrightarrow[293 \text{ K}]{OH^-} \text{'A' (Major product)}$