The major products A and B in the following r | vedclass

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(D) Reaction $(i)$: Benzene reacts with $Cl_2$ in the presence of $uv$ light at $500 \ K$ to undergo free radical addition,forming $1,2,3,4,5,6$-hexac

Vedclass · Accepted Answer

$A$ = Hexachlorocyclohexane $(BHC)$,$B$ = $1-$Iodo$-1-$methylcyclohexane

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(D) Reaction $(i)$: Benzene reacts with $Cl_2$ in the presence of $uv$ light at $500 \ K$ to undergo free radical addition,forming $1,2,3,4,5,6$-hexachlorocyclohexane (also known as $BHC$ or $Gammexane$).Reaction (ii): $1$-Methylcyclohexene reacts with $HI$ via electrophilic addition following Markovnikov's rule. The proton $(H^+)$ adds to the less substituted carbon of the double bond,and the iodide ion $(I^-)$ adds to the more substituted carbon,resulting in $1$-iodo-$1$-methylcyclohexane.

The major products $A$ and $B$ in the following reactions are respectively:
i) Benzene $\xrightarrow{Cl_2/uv, 500K} A$
ii) $1-$Methylcyclohexene $\xrightarrow{HI} B$

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The major products $A$ and $B$ in the following reactions are respectively:i) Benzene $\xrightarrow{Cl_2/uv, 500K} A$ii) $1-$Methylcyclohexene $\xrightarrow{HI} B$