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(C) Temporary hardness of water is removed by Clark's process,where slaked lime,$Ca(OH)_2$,is added to hard water. The chemical reactions involved are

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$Mg(OH)_2; CaCO_3$

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(C) Temporary hardness of water is removed by Clark's process,where slaked lime,$Ca(OH)_2$,is added to hard water. The chemical reactions involved are: $Ca(HCO_3)_{2(aq)} + Ca(OH)_{2(aq)} \rightarrow 2CaCO_{3(s)} + 2H_2O_{(l)}$ $Mg(HCO_3)_{2(aq)} + 2Ca(OH)_{2(aq)} \rightarrow 2CaCO_{3(s)} + Mg(OH)_{2(s)} + 2H_2O_{(l)}$ Note: In the case of magnesium bicarbonate,the product is magnesium hydroxide,$Mg(OH)_2$,due to its lower solubility product compared to $MgCO_3$. Thus,the insoluble precipitates formed are $Mg(OH)_2$ and $CaCO_3$.

The major products during the removal of temporary hardness of water are

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