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(C) $1$. The starting material is anisole $(C_6H_5OCH_3)$. The $-OCH_3$ group is strongly activating and ortho/para-directing.$2$. Nitration with $HNO

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(C) $1$. The starting material is anisole $(C_6H_5OCH_3)$. The $-OCH_3$ group is strongly activating and ortho/para-directing.$2$. Nitration with $HNO_3/H_2SO_4$ primarily yields the para-substituted product due to steric hindrance at the ortho position. Thus,$A$ is $p$-nitroanisole.$3$. In the next step,$p$-nitroanisole reacts with excess $Br_2$ in the presence of $Fe$. The $-OCH_3$ group is a stronger activating group than the $-NO_2$ group is deactivating. Therefore,the bromination occurs at the positions ortho to the $-OCH_3$ group. Since the para position is already occupied by the $-NO_2$ group,both ortho positions are brominated to form $B$,which is $2,6$-dibromo-$4$-nitroanisole.$4$. Comparing this with the given options,option $C$ represents the correct structures for $A$ and $B$.

The major products formed in the following reaction sequence are:
(Image)
$A$ and $B$ respectively are:

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The major products formed in the following reaction sequence are:(Image)$A$ and $B$ respectively are: